JSONObject 转 Map 并使用 Lambda 表达式；应用场景：调用第三方接口。
JSONObject jsonObject = new JSONObject();
Object[] objects = {"1", "2", "3", "4"};
Object[] objects1 = {"11", "22", "33", "44"};
Object[] objects2 = {"111", "222", "333", "444"};
Object[] objects3 = {"xxx123456"};
jsonObject.put("A", objects);
jsonObject.put("B", objects1);
jsonObject.put("C", objects2);
jsonObject.put("password", objects3);
// JSONObject 转 Map
Map<String, String> a = JSONObject.parseObject(jsonObject.toJSONString(), new TypeReference<Map<String, String>>() {
});
System.out.println("-----------：" + jsonObject);
System.out.println("-----------：" + a);
StringBuilder stringBuilder = new StringBuilder();
a.forEach((key, values) -> {
stringBuilder.append(key).append("=");
if ("password".equalsIgnoreCase(key)) {
stringBuilder.append("*****");
} else {
stringBuilder.append(values);
}
stringBuilder.append("&");
});
stringBuilder.deleteCharAt(stringBuilder.length() - 1);
System.out.println("-----------：" + stringBuilder);
}
// 输出：
-----------：{"A":["1","2","3","4"],"B":["11","22","33","44"],"password":["xxx123456"],"C":["111","222","333","444"]}
-----------：{A=["1","2","3","4"], B=["11","22","33","44"], password=["xxx123456"], C=["111","222","333","444"]}
-----------：A=["1","2","3","4"]&B=["11","22","33","44"]&password=*****&C=["111","222","333","444"]
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版权声明：本文由 Ian 在 2019年04月02日发表。本文采用CC BY-NC-SA 4.0许可协议，非商业转载请注明出处，不得用于商业目的。
文章题目及链接：《JSONObject 转 Map》
